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Recipe 6.4. Storing Pointers in a vector
Problem
For efficiency or other reasons, you can't store copies of your objects in a vector, but you need to keep
track of them somehow.
Solution
Store pointers to your objects in a vector instead of copies of the objects themselves. But if you do,
don't forget to delete the objects that are pointed to, because the vector won't do it for you. Example 6-4
shows how to declare and work with vectors of pointers.
Example 6-4. Using vectors of pointers
#include <iostream>
#include <vector>
using namespace std;
static const int NUM_OBJECTS = 10;
class MyClass { /*...*/ };
int main( ) {
vector<MyClass*> vec;
MyClass* p = NULL;
// Load up the vector with MyClass objects
for (int i = 0; i < NUM_OBJECTS; i++) {
p = new MyClass( );
vec.push_back(p);
}
// Do something useful with this data, then delete the objects when
// you're done
for (vector<MyClass*>::iterator pObj = vec.begin( );
pObj != vec.end( ); ++pObj) {
delete *pObj; // Note that this is deleting what pObj points to,
// which is a pointer
}
vec.clear( ); // Purge the contents so no one tries to delete them
// again
}
Discussion
You can store pointers in a vector just like you would anything else. Declare a vector of pointers like
this:
vector<MyClass*> vec;
The important thing to remember is that a vector stores values without regard for what those values
represent. It, therefore, doesn't know that it's supposed to delete pointer values when it's destroyed. If
you allocate memory, then put pointers to that memory in a vector, you have to delete the memory
yourself when you are done with it. Don't be fooled by the term "container" into thinking that somehow
when you store a pointer in a vector that it assumes ownership.
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Recipe 6.5. Storing Objects in a list
Problem
You need to store items in a sequence, but your requirements don't match up well with a vector.
Specifically, you need to be able to efficiently add and remove items in the middle of the sequence, not
just at the end.
Solution
Use a list, declared in <list>, to hold your data. lists offer better performance and more flexibility when
modifying the sequence at someplace other than the beginning or the end. Example 6-5
shows you how
to use a list, and shows off some of its unique operations.
Example 6-5. Using a list
#include <iostream>
#include <list>
#include <string>
#include <algorithm>
using namespace std;
// A simple functor for printing
template<typename T>
struct printer {
void operator( )(const T& s) {
cout << s << '\n';
}
};
bool inline even(int n) {
return(n % 2 == 0);
}
printer<string> strPrinter;
printer<int>    intPrinter;
int main( ) {
list<string> lstOne;
list<string> lstTwo;
lstOne.push_back("Red");
lstOne.push_back("Green");
lstOne.push_back("Blue");
lstTwo.push_front("Orange");
lstTwo.push_front("Yellow");
lstTwo.push_front("Fuschia");
for_each(lstOne.begin( ), // Print each element in the list
lstOne.end( ),   // with a custom functor, print
strPrinter);
lstOne.sort( );           // list has a member for sorting
lstTwo.sort( );
lstOne.merge(lstTwo);    // Merge the two lists and print
for_each(lstOne.begin( ), // the results (the lists must be
lstOne.end( ),   // sorted before merging)
strPrinter);
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Recipe 6.6. Mapping strings to Other Things
Problem
You have objects that you need to store in memory, and you want to store them by their string keys.
You need to be able to add, delete, and retrieve items quickly (with, at most, logarithmic complexity).
Solution
Use the standard container map, declared in <map>, to map keys (strings) to values (any type that
obeys value semantics). Example 6-6
shows how.
Example 6-6. Creating a string map
#include <iostream>
#include <map>
#include <string>
using namespace std;
int main( ) {
map<string, string> strMap;
strMap["Monday"]    = "Montag";
strMap["Tuesday"]   = "Dienstag";
strMap["Wednesday"] = "Mittwoch";
strMap["Thursday"]  = "Donnerstag";
strMap["Friday"]    = "Freitag";
strMap["Saturday"]  = "Samstag";
// strMap.insert(make_pair("Sunday", "Sonntag"));
strMap.insert(pair<string, string>("Sunday", "Sonntag"));
for (map<string, string>::iterator p = strMap.begin( );
p != strMap.end( ); ++p ) {
cout << "English: " << p->first
<< ", German: " << p->second << endl;
}
cout << endl;
strMap.erase(strMap.find("Tuesday"));
for (map<string, string>::iterator p = strMap.begin( );
p != strMap.end( ); ++p ) {
cout << "English: " << p->first
<< ", German: " << p->second << endl;
}
}
Discussion
A map is an associative container that maps keys to values, provides logarithmic complexity for inserting
and finding, and constant time for erasing single elements. It is common for developers to use a map to
keep track of objects by using a string key. This is what Example 6-6
does; in this case, the mapped type
happens to be a string, but it could be nearly anything.
A map is declared like this:
map<typename Key,                          // The type of the key
typename Value,                        // The type of the value
typename LessThanFun = std::less<Key>, // The function/functor
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